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BTW, there's light at the end of the Alpa tunnel at least for wide angles with T/S although we've just got to wait it out, focus stack and listen to the Arca and Cambo folks in the meantime.Arca , Alpa just eat my dust. Lol
I just had to get my dig in since I keep forgetting the myths around here on our inferior Cambo. Oh wait did i just say that mister neutral. Okay relax I'm just freaking teasing.
Whatsa matta, can't expose correctly for snow?Since my height is about half way between Guy and Jack, I guess I'll just average their advice... LOL!
Thanks for the great information, I'll have plenty of ideas to test out before heading to Hawaii next month. It's amazing how my inspiration adapts to the weather, Hawaii and India in January, Tuscany in the spring, Alaska in June. Life is good.
Merry Christmas to all!
198.9 cm to be preciseFrom this, we can conclude that Jack is tall.
Really? Here I thought you were taller. Heck, I'm only 205.7 cm......198.9 cm to be precise
It is more about Maths than Myths, but I thought it was ArcSin(f/j), and you calculate your tilt angle and set it before you start trying to focus... it is, of course, different if you are using a Sinar or a CAPcam... if you really want to know read Merklinger's "Focusing the view camera"... and this is independent of photographer's height - J could be 20 feet - or meters.The correct formula, ArcSin( f / d ), is fortunately very very close to simply ( f / d ) as long as you're not doing macro. The problem is one of units, as the ratio ( f / d ) is in radians. (Note that radians, being the ratio of two lengths, are actually dimensionless units!) To translate into degrees, which is what most cameras are marked in, multiply by 180 / Pi, or about 57.3 ... actually, 60 is probably good enough, so taking the example of a 90mm (that's 0.09 meters) lens 1 meter off the ground, we get 60 * 0.09 / 1, or 5.4 degrees. The correct answer is 5.2 degrees.
Now we can see where Jack's rule comes from. For a 2 meter camera height, the formula gives a tilt of 57 * f / 2. For an extra degree of tilt, the focal length would have to increase by 2/57, or 0.0351 meters = 35.1mm. From this, we can conclude that Jack is tall.
Why yes, I was a math professor.:ROTFL:
Matt