# Line slope calculator 2x+5y=52

**Straight line given by points A[1; 10] and B[6; 8]**

## Calculation:

**Slope-intercept form of line:**y = -0.4x+10.4

**Canonical form of the line equation:**2x+5y-52 = 0

**Parametric form of the line equation:**

x = 5t+1

y = -2t+10 ; t ∈ R

**Slope:**m = -0.4

**Slope angle of line: φ =**-21°48'5″ = -0.3805 rad

**X intercept:**x

_{0}= 26

**Y intercept:**y

_{0}= q = 10.4

**Distance line from the origin:**d

_{0}= 9.6562

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; -2)

**Normal vector: n =**(2; 5)

**Midpoint of the segment AB: M =**[3.5; 9]

**Perpendicular Bisector equation:**5x-2y+0.5 = 0

**Vector OA = (1; 10) ; |OA| = 10.0499**

**Vector OB = (6; 8) ; |OB| = 10**

**Scalar product OA .OB = 86**

**Angle ∠ AOB = 31°9'33″ = 0.5438 rad**